SSC JE Mechanical Engineering 27th Jan 2018 Shift-2

Instructions

For the following questions answer them individually

Question 171

The total force acting on a plane horizental surface in a liquid is equal to (given that w = Specific weight of water, X = Depth of liquid, A = Area of Surface)
(a) $$w \overline{x}A$$
(b) $$w \overline{x}$$
(c) $$\frac{w \overline{x}}{A}$$
(d) $$\frac{Aw}{\overline{x}}$$

Video Solution

Question 172

A uniform flow is one when

Video Solution

Question 173

The flow at critical depth in a open channel is

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Question 174

The maximum headlossin a pipe with bend angle

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Question 175

The property ofa fluid which determinesits resistance to shearing stressesis called

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Question 176

The force per unit areais called

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Question 177

The resultant pressure (p) of the liquid on a immersed surface will act at

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Question 178

A venturimeteris used to measure discharge through

Video Solution

Question 179

The frictional resistance independent of

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Question 180

The motion of whirlpoolin a river is

Video Solution

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SSC Content

SSC JE Mechanical Engineering 27th Jan 2018 Shift-2

The total force acting on a plane horizental surface in a liquid is equal to (given that w = Specific weight of water, X = Depth of liquid, A = Area of Surface)(a) $$w \overline{x}A$$(b) $$w \overline{x}$$(c) $$\frac{w \overline{x}}{A}$$(d) $$\frac{Aw}{\overline{x}}$$

A uniform flow is one when

The flow at critical depth in a open channel is

The maximum headlossin a pipe with bend angle

The property ofa fluid which determinesits resistance to shearing stressesis called

The force per unit areais called

The resultant pressure (p) of the liquid on a immersed surface will act at

A venturimeteris used to measure discharge through

The frictional resistance independent of

The motion of whirlpoolin a river is

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CAT Quant Questions | CAT Quantitative Ability

CAT DILR Questions | LRDI Questions For CAT

CAT Verbal Ability Questions | VARC Questions For CAT

The total force acting on a plane horizental surface in a liquid is equal to (given that w = Specific weight of water, X = Depth of liquid, A = Area of Surface)
(a) $$w \overline{x}A$$
(b) $$w \overline{x}$$
(c) $$\frac{w \overline{x}}{A}$$
(d) $$\frac{Aw}{\overline{x}}$$