For the following questions answer them individually
Two tangents PA and PBare drawn to a circle with centre O from an external point P. If $$\angle OAB = 30^\circ$$, then $$\angle APB$$ is:
ABC is an equilateral triangle. P,Q and R are the midpoints of sides AB,BC and CA, respectively. If the length of the side of the triangle ABC is 8 cm, then the area of $$ \triangle PQR $$ is:
Solve the following.
$$\frac{\sin 40^\circ}{\cos 50^\circ} + \frac{\cosec 50^\circ}{\sec 40^\circ} - 4 \cos 50^\circ \cosec 40^\circ$$
The average of the marks of 30 boys is 88, and when the top two scores were excluded, the average marks reduced to 87.5. If the top two scores differ by 2, then the highest mark is:
If $$x \cos A - y \sin A = 1$$ and $$x \sin A + y \cos A = 4$$, then the value of $$17x^{2} + 17y^{2}$$ is:
A circular disc of area $$0.64\pi m^{2}$$ rolls down a length of 1.408 km. The number of revolutions it makes is:Â
(Taken $$\pi = \frac{22}{7}$$).
An article was sold at a gain of 18%. If it had been sold for ₹ 49 more, then the gain would have been 25%. The cost price of the article is:
If $$3^{a}=27^{b}=81^{c}$$ and $$abc=144$$, then the value of $$12(\frac{1}{a}+\frac{1}{2b}+\frac{1}{5c})$$ is:
If $$a+b+c=9$$ and $$ab+bc+ca=-22$$, then the value of  $$a^{3}+b^{3}+c^{3}-3abc$$ is:
A shopkeeper marks the price of an article in such a way that after allowing a discount of 22%, he gets a gain of 11%.If the marked price is Rs.888, then the cost price of the article is:
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