NTA JEE Mains 22nd Jan 2026 Shift 1

A 'p'-block element (E) and hydrogen form a binary cation $$(EH_{x})^{+}$$ , while $$EH_{3}$$ on treatment with $$K_{2}HgI_{4}$$ in alkaline medium gives a precipitate of basic mercury(II)amido- iodine. Given below are first ionisation enthalpy values ($$kJ mol^{-1}$$) for first element each from group 13, 14, 15 and 16. Identify the correct first ionisation enthalpy value for element E.

Given below are two statements:
Statement I: Benzene is nitrated to give nitrobenzene, which on further treatment

Statement II: -$$NO_{2}$$ group is a m-directing, and deactivating group.

In the light of the above statements, choose the most appropriate answer from the options given below

Given below are two statements:

Statement I: Phenol on treatment with . $$CHCL_{3}$$/aq. $$KOH$$ under refluxing condition, followed by acidification produces $$p$$-hydroxy benzaldehyde as the major product and $$o$$-hydroxy benzaldehyde as the minor product.

Statement II: The mixture of $$p$$-hydroxybenzaldehyde and $$o$$-
hydroxybenzaldehyde can be easily separated through steam distillation.

In the light of the above statements, choose the correct answer from the options given below

A first row transition metal (M) does not liberate $$H_{2}$$ gas from dilute HCI. 1 mol of aqueous solution of $$MSO_{4}$$ is treated with excess of aqueous KCN and then $$H_{2} S(g)$$ is passed through the solution. The amount of MS (metal sulphide) formed from the above reaction is _______ mol.

Consider the transition metal ions $$Mn^{3+}, Cr^{3+}, Fe ^{3+}$$ and $$Co^{3+}$$ and all form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective d-orbitals of the complexes is

Two p-block elements $$X$$ and $$Y$$ form fluorides of the type $$EF_{3}$$. The fluoride compound $$XF_{3}$$ is a Lewis acid and $$YF_{3}$$ is a Lewis base. The hybridizations of the central atoms of $$XF_{3}$$ and $$YF_{3}$$ respectively are

'A' is a neutral organic compound $$(M.F : C_{8}H_{9}ON)$$. On treatment with aqueous $$Br_{2}/Ho_{(-)}$$, 'A' forms a compound 'B' which is soluble in dilute acid. 'B' on treatment with aqueous $$NaNO_{2} / HCl (0-5^{o}C)$$ produces a compound 'C' which on treatment with $$CuCN/NaCN$$ produces 'D'. Hydrolysis of 'D' produces 'E' which is also obtainable from the hydrolysis of'A'. 'E' on treatment with acidified $$KMnO_{4}$$ produces 'F'. 'F' contains two different types of hydrogen atoms. The structure of 'A' is

Match the LIST-I with LIST-II

Table

Choose the correct answer from the options given below:

In the reaction,
$$ 2Al(s)+6HCl(aq)\rightarrow2Al^{3+}(aq)+6cl^{-}(aq)+3H_{2}(g)$$

The correct order of reactivity of $$CH_{3} Br$$ in methanol with the following
nucleophiles is

$$F^{-}, I^{-}, C_{2}H_{5}O^{-}$$ and $$C_{6}H_{5}O^{-}$$