Two taps A and B can fill a tank independently in 10 and 15 minutes respectively while C empties the full tank in 20 minutes. If all the three are opened for 1 minute and C is closed then extra time (in minutes) to get the tank filled is
Let capacity of the tank = 60 liters.
Hence, capacities of the taps respectively are:
A = 6 liters/min
B = 4 liters/min
C = -3 liters/min (minus because it drains the tank)
When all three are opened for a minute, tank filled = 6+4-3 = 7 liters
Tank remaining to be filled = 53 liters
Time needed now to fill the tank = 53/10 = 5.3 minutes
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