Instructions

In each of these questions, two equations are given. You have to solve these equations and nd out the values of x and y and :
Give answer
a:if x < y
b: if x > y
c: if x ≤ y
d: if x ≥ y
e: if x = y

Question 96

I. $$8x^{2} + 6x = 5$$
II. $$12y^{2} - 22y + 8 = 0$$

Solution

I : $$8x^{2} + 6x - 5 = 0$$

=> $$8x^2 - 4x + 10x - 5 = 0$$

=> $$4x (2x - 1) + 5 (2x - 1) = 0$$

=> $$(4x + 5) (2x - 1) = 0$$

=> $$x = \frac{-5}{4} , \frac{1}{2}$$

II : $$12y^{2} - 22y + 8 = 0$$

=> $$12y^2 - 6y - 16y + 8 = 0$$

=> $$6y (2y - 1) - 8 (2y - 1) = 0$$

=> $$(6y - 8) (2y - 1) = 0$$

=> $$y = \frac{1}{2} , \frac{4}{3}$$

$$\therefore x \leq y$$


Create a FREE account and get:

  • Banking Quant Shortcuts PDF
  • Free Banking Study Material - (15000 Questions)
  • 135+ Banking previous papers with solutions PDF
  • 100+ Online Tests for Free

cracku

Boost your Prep!

Download App