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If the length of a rectangle is increased by 15% and its breadth is decreased by 20%, then it area
Let the length and breadth of the rectangle is a and b.
Area of the rectangle $$=ab$$
As per the condition given in the question, new length of the rectangle = 1.15a and 0.8b
Hence, new area of the rectangle $$=1.15a\times 0.8b=0.92ab$$
So, the required area $$=\dfrac{(ab-0.92ab)\times 100}{ab}=8\%$$
Hence the area of the new rectangle decreased by $$8\%$$.
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