[Solved] Let the point (-1, \\alpha, \\beta) lie on the line of the shortest distance between the lines \\frac{x+2}{-3} = \\frac{y-2}{4} = \\frac{z-5}{2} and \\frac{x+2}{-1} = \\frac{y+6}{2} = \\frac{z-1}{0}. Then (\\alpha - \\beta)^2 is equal to __________ - - NTA JEE Mains 05th April 2024 Shift 2