In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer If
a:x > y
b: x ≥ y
c: x < y
d: x ≤ y
e: x = y or the relationship cannot be established
$$I. x^{2}- 6x + 9 = 0$$
$$II. y^{2} - 11y+24 = 0$$
I. $$x^{2}$$ -6x+9=0
$$(x-3)^{2} =0$$
x-3=0
x=3
II. $$y^{2}$$ -11y+24=0
$$y^{2}$$ -8y-3y+24=0
y(y-8) - 3(y-8)=0
(y-3)(y-8)=0
y=3 or 8
Hence , x ≤ y
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