Sign in
Please select an account to continue using cracku.in
↓ →
The pressure and volume of an ideal gas are related as $$PV^{3/2} = K$$ (Constant). The work done when the gas is taken from state $$A(P_1, V_1, T_1)$$ to state $$B(P_2, V_2, T_2)$$ is :
PV^(3/2) = K. W = ∫PdV = ∫K/V^(3/2)dV = K[-2/V^(1/2)] = -2K(1/√V₂ - 1/√V₁)
= 2K(1/√V₁ - 1/√V₂) = 2(P₁V₁^(3/2)/√V₁ - P₂V₂^(3/2)/√V₂) = 2(P₁V₁ - P₂V₂).
The correct answer is Option 1.
Create a FREE account and get:
Educational materials for JEE preparation