Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the odd letter-cluster.
Solution
J + 4 = N + 3 = Q + 2 = S T + 2 = V + 2 = X + 2 = Z R + 1 = S + 1 = T + 1 = U A + 3 = D + 3 = G + 3 = J Except option A, remaining all letter-clusters have same difference in between the letters. $$\therefore$$ The correct answer is option A.
