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A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.
1, 0.25, 1/9, ? , 0.04, 1/36
Numbers of the form $$'\frac{1}{n^2}'$$ are written.
$$\frac{1}{1^2}$$ = 1
$$\frac{1}{2^2}$$ = $$\frac{1}{4}$$ = 0.25
$$\frac{1}{3^2}$$ = $$\frac{1}{9}$$
$$\frac{1}{4^2}$$ = $$\frac{1}{16}$$ = 0.0625
$$\frac{1}{5^2}$$ = $$\frac{1}{25}$$ = 0.04
$$\frac{1}{6^2}$$ = $$\frac{1}{36}$$
=> Ans - (A)
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