Question 89

What is the area of the jogging track which is 2 m wide that runs along the area of a rectangle 20 m $$\times$$ 18 m inside it?

Solution

area of outer rectangle = $$ 24 \times 22 = 528 $$

area of inner rectangle = $$ 20 \times 18 = 360 $$

area of the jogging track which is 2 m wide = 528 - 360 = $$ 168 m^2 $$


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