Question 89
The radius of the base of a right circular cylinder is r and the radius of a sphere is $$\frac{r}{2}$$. If the volumes of that cylinder and the sphere are equal, then the height of the circular cylinder in proper units is
Solution
Volume of Cylinder =V=$$\pi r^2 h$$
Volume of sphere V=$$\frac{4}{3}\times \pi (r/2)^3$$
Cylinder Volume = Sphere Volume
So $$\pi \times r^2 \times h = \frac{4}{3} \times \pi \times (r/2)^3$$
$$h=r/6$$
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