What is the minimum number of square tiles required to pave a floor of dimensions 24.78 meters x 22.26 meters?
HCF 2478 2226
252
$$2 \times 126$$
$$2 \times 18 \times 7$$
HCF = $$2 \times 3 \times 7$$
= 42
No.of tiles $$2478 \times 2226$$
42 $$\times$$ 42
$$\Rightarrow 59 \times 53$$
= 3127
Hence the answer is option B
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