Solution
The largest power of 7 that divides $$(68)!$$ = Sum of the quotients of {$$\frac{68}{7}$$, $$\frac{68}{7^2}$$, $$\frac{68}{7^3}$$, .......}
= Sum of the quotients of {$$\frac{68}{7}$$, $$\frac{68}{49}$$, $$\frac{68}{343}$$, .......}
= 9 + 1 + 0 + 0 + .....
= 10
$$\therefore\ $$n = 10
Hence, the correct answer is Option B
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