Question 82

The least value of k such that $$315 \times k$$ is a perfect square is

Solution

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315 x k = 3 x 3 x 5 x 7 x k
To make the LHS a perfect square, k should definitely have at least one power of 5 and 7. 
For the least value of k, we should have only the minimum requirements i.e. k = 5 x 7 
hence, value of k must be 35. 

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