Question 81

What is the total surface area of a solid cylinder whose radius is half the radius of a circle of area 154 m and height is the same as its radius?

Solution

areaof circle = $$\pi\times r^2$$

154 m = $$\pi\times r^2$$

r = 7 m

cyclinder

height H = radius of circle r

R = $$\frac{7}{2}= 3.5m$$

TSA = $$2\pi\times R\times(R+H)$$

=$$2\pi\times 3.5\times(3.5+7)$$

= $$231 m^{2}$$

Create a FREE account and get: