What is the total surface area of a solid cylinder whose radius is half the radius of a circle of area 154 m and height is the same as its radius?
areaof circle = $$\pi\times r^2$$
154 m =Â $$\pi\times r^2$$
r = 7 m
cyclinder
height H = radius of circle r
R = $$\frac{7}{2}= 3.5m$$
TSA = $$2\pi\times R\times(R+H)$$
   =$$2\pi\times 3.5\times(3.5+7)$$
   = $$231 m^{2}$$
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