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A company has two plants $$A$$ and $$B$$ to manufacture motorcycles. 60% motorcycles are manufactured at plant $$A$$ and the remaining are manufactured at plant $$B$$. 80% of the motorcycles manufactured at plant $$A$$ are rated of the standard quality, while 90% of the motorcycles manufactured at plant $$B$$ are rated of the standard quality. A motorcycle picked up randomly from the total production is found to be of the standard quality. If $$p$$ is the probability that it was manufactured at plant $$B$$, then $$126p$$ is
P(A) = 0.6, P(B) = 0.4. P(Quality|A) = 0.8, P(Quality|B) = 0.9.
P(Quality) = 0.6Ă—0.8 + 0.4Ă—0.9 = 0.48 + 0.36 = 0.84.
p = P(B|Quality) = 0.36/0.84 = 36/84 = 3/7.
126p = 126 Ă— 3/7 = 54.
The correct answer is Option (1): 54.
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