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If three marbles are drawn at random, what is the probability that none is green?
Out of the fourteen marbles four are green in colour
Subtracting the green marbles from the total marbles we will be left with 10 marbles
Out of ten marbles three can be choosen in 10C3 ways
Probability of not choosing a choosing marble = 10C3/14C3 = $$\frac{30}{91}$$
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