Question 76

If $$\sin A = \frac{1}{2}$$ and $$A$$ and $$B$$ are complementary angles, then find the value of $$\sin (A - B)$$.


According to question, $$A+B=90^{\circ\ }.$$

$$\sin\left(A-B\right)=\sin A\cos B-\sin B\cos A$$

=$$SinASinA-\left(CosA\right)CosA.\ \ \left(As\ Cos\left(90-A\right)=SinA\right).$$







C is correct choice.

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