The complex of $$Ni^{2+}$$ ion and dimethyl glyoxime contains ________ number of Hydrogen (H) atoms.

We need to find the number of hydrogen atoms in the complex of $$Ni^{2+}$$ with dimethylglyoxime (DMG).

Dimethylglyoxime has the molecular formula $$C_4H_8N_2O_2$$. Its structure is:

$$CH_3-C(=NOH)-C(=NOH)-CH_3$$

Each DMG molecule has 8 hydrogen atoms (6 from two $$CH_3$$ groups and 2 from two $$-OH$$ groups).

$$Ni^{2+}$$ forms a square planar complex with two molecules of dimethylglyoxime. Each DMG molecule acts as a bidentate ligand, coordinating through its two nitrogen atoms. The complex is commonly called "nickel dimethylglyoximate" and has the formula $$Ni(DMG)_2$$ or $$[Ni(C_4H_7N_2O_2)_2]$$.

When DMG coordinates with $$Ni^{2+}$$, each DMG molecule loses one proton (from one of its $$-OH$$ groups) to form the anionic ligand $$DMGH^-$$. Since the complex uses two DMG molecules and $$Ni^{2+}$$ has a +2 charge:

- Each DMG loses 1 H: $$8 - 1 = 7$$ H atoms per ligand

- Two ligands contribute: $$7 \times 2 = 14$$ H atoms

The two $$DMGH^-$$ ligands in the complex are held together by intramolecular hydrogen bonds (O-H...O) between the oxime groups, which is a characteristic feature of this complex and gives it additional stability.

The answer is 14.