A sum of ₹4,360 was to be divided among A,B, C and D in the ratio of 3 : 4: 5 : 8, but it was divided in the ratio of $$\frac{1}{3} : \frac{1}{4} : \frac{1}{5} : \frac{1}{8}$$ by mistake. As a result:

Sum was to be divided in the ratio 3:4:5:8

Let the sum of A,B,C and D is 3x,4x,5x and 8x respectively

According to question, 

we get 20x=4360
x=218
so we get A=654 ; B =872 ; 1090;D=1744
But by mistake it was divided in the ratio ; $$\frac{1}{3}:\frac{1}{4}:\frac{1}{5}:\frac{1}{8}$$

By Equating , the ratio will be   ;  40 : 34 : 24 : 15

New sum of A, B, C and D will be 40x, 30x, 24x and 15x respectively

Solving in the same way, we get 

A = 1600 , B = 1200, C = 960 and D = 600

So we can say D got 1144 less

Hence Option A is correct.