If the radius of a circle is increased by 6%,then the area of the circle is increased by
Let radius of circle be $$r=1$$ units
=> Area = $$\pi r^2=\pi$$ sq.units
Now, after 6% increase, new radius = $$r'=1.06$$ units
=> New area = $$\pi(r')^2=1.1236\pi$$ sq. units
$$\therefore$$ Increase in area = $$\frac{1.1236-1}{1}\times100=12.36\%$$
=> Ans - (D)