If $$f(x) = \begin{cases} x^3 \sin\left(\frac{1}{x}\right), & x \neq 0 \\ 0, & x = 0 \end{cases}$$ then

A

$$f''\left(\frac{2}{\pi}\right) = \frac{24 - \pi^2}{2\pi}$$

B

$$f''\left(\frac{2}{\pi}\right) = \frac{12 - \pi^2}{2\pi}$$

C

$$f''(0) = 1$$

D

$$f''(0) = 0$$