If a point $$P(\alpha, \beta, \gamma)$$ satisfying $$(\alpha \; \beta \; \gamma) \begin{pmatrix} 2 & 10 & 8 \\ 9 & 3 & 8 \\ 8 & 4 & 8 \end{pmatrix} = (0 \; 0 \; 0)$$ lies on the plane $$2x + 4y + 3z = 5$$, then $$6\alpha + 9\beta + 7\gamma$$ is equal to

A

$$\dfrac{5}{4}$$

B

-1

C

11

D

$$\dfrac{11}{5}$$