Given that the lengths of the paths of a ball thrown with different speeds by twoboysare the same,if they take 0.6 seconds and 1 second respectively to cover the said length, whatis the average speed oftravel for the first throw, if the same for the second is 96 km/h?
Length= $$Speed\times time$$
Given lenght is same,
$$S1\times T1$$=$$S2\times T2$$
$$S1\times \frac{6}{36000}=96\times\frac{1}{3600} $$
$$S1=16\times10$$=160 km/h
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