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Question 71

Let $$f: R \to R$$ be defined as
$$f(x) = \begin{cases} \frac{\lambda x^2 - 5x + 6}{\mu(5x - x^2 - 6)} & x < 2 \\ e^{\frac{\tan(x-2)}{x - [x]}} & x > 2 \\ \mu & x = 2 \end{cases}$$
where $$[x]$$ is the greatest integer less than or equal to $$x$$. If $$f$$ is continuous at $$x = 2$$, then $$\lambda + \mu$$ is equal to:

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