Question 71

In a 60 liter solution of acid and water, the ratio of acid and water is 3 : 7. How much(in liter) acid is to be mixed in the solution so that the ratio of acid and water in the resulting solution is 1 : 2?

Solution

In a 60 liter solution of acid and water, the ratio of acid and water is 3 : 7.

quantity of acid initially = $$60\times\ \frac{3}{10}$$ = 18

quantity of water initially = $$60\times\ \frac{7}{10}$$ = 42

Let's assume the quantity of acid mixed in the solution is 'y'.

$$\frac{18+y}{42}\ =\ \frac{1}{2}$$

36+2y = 42

2y = 42-36 = 6

quantity of acid mixed in the solution = y = 3

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