Question 70

A, B and C have amounts in the ratio of 3 : 4 : 5. First B gives $$\frac{1}{4^{th}}$$ to A and $$\frac{1}{4^{th}}$$ to C then C gives $$\frac{1}{6^{th}}$$ to A. What is the final ratio of amount of A, B and C respectively?

Solution

Let amount with A, B and C be Rs. $$300,400,500$$ respectively.

First, B gives $$\frac{1}{4^{th}}$$ to A and $$\frac{1}{4^{th}}$$ to C

=> Amount with A = $$300+\frac{1}{4}\times400=Rs.$$ $$400$$

C = $$500+\frac{1}{4}\times400=Rs.$$ $$600$$

B = $$400-100-100=Rs.$$ $$200$$

Secondly, C gives $$\frac{1}{6^{th}}$$ to A

=> Amount with A = $$400+\frac{1}{6}\times600=Rs.$$ $$500$$

B = $$Rs.$$ $$200$$

C = $$600-100=Rs.$$ $$500$$

Thus, final ratio with A:B:C = 5:2:5

=> Ans - (D)


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