The bulk modulus of a liquid is $$3 \times 10^{10}$$ Nm$$^{-2}$$. The pressure required to reduce the volume of liquid by $$2\%$$ is :

We are given: Bulk modulus $$B = 3 \times 10^{10}$$ N/m$$^2$$, volume reduction $$= 2\% = 0.02$$.

Recall the formula for bulk modulus: $$ B = \frac{\Delta P}{\frac{\Delta V}{V}} $$

where $$\Delta P$$ is the pressure applied and $$\frac{\Delta V}{V}$$ is the fractional change in volume.

Solve for the required pressure: $$ \Delta P = B \times \frac{\Delta V}{V} $$

$$ \Delta P = 3 \times 10^{10} \times 0.02 $$

$$ \Delta P = 6 \times 10^{8} \text{ N m}^{-2} $$

Therefore, the correct answer is Option B.