JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Heat energy of 735 J is given to a diatomic gas allowing the gas to expand at constant pressure. Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal energy of the gas will be:
Heat energy $$Q = 735$$ J given to a diatomic gas at constant pressure. The gas molecules rotate but do not oscillate.
Diatomic gas with rotation, no oscillation: $$f = 5$$ (3 translational + 2 rotational).
$$C_v = \frac{5}{2}R$$ $$C_p = \frac{7}{2}R$$At constant pressure: $$Q = nC_p\Delta T$$ and $$\Delta U = nC_v\Delta T$$.
$$\frac{\Delta U}{Q} = \frac{C_v}{C_p} = \frac{5/2}{7/2} = \frac{5}{7}$$ $$\Delta U = \frac{5}{7} \times Q = \frac{5}{7} \times 735 = 525 \text{ J}$$The answer is Option A: 525 J.
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.