Solution
$$x+3y+2=0$$
x + 3y = -2
Taking cube both sides,
$$(x + 3y)^3 = -8$$
$$x^3 + 27y^3 + 3x.3y(x + 3y) = -8$$
$$x^3 + 27y^3 + 9xy(-2) = -8 $$
$$x^{3}+27y^{3} -18xy = -8$$
$$x^{3}+27y^{3}+8-18xy$$ = 0
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