Question 66

The value of $$\frac{8 \div [(8 - 3) \div \left\{(4 \div 4 of 8) + 4 - 4 \times 4 \div 8\right\} - 2]}{8 \times 8 \div 4 - 8 \div 8 of 2 - 7}$$ is:

Solution

$$\frac{8 \div [(8 - 3) \div \left\{(4 \div 4 of 8) + 4 - 4 \times 4 \div 8\right\} - 2]}{8 \times 8 \div 4 - 8 \div 8 of 2 - 7}$$

$$\frac{8 \div [(8 - 3) \div \left\{(4 \div 32) + 4 - 4 \times 4 \div 8\right\} - 2]}{8 \times 8 \div 4 - 8 \div 16 - 7}$$

$$\frac{8 \div [5 \div \left\{\frac{1}{8} + 4 - 4 \times \frac{1}{2}\right\} - 2]}{8 \times 2 - \frac{1}{2} - 7}$$

$$\frac{8 \div [5 \div \left\{\frac{1}{8} + 4 - 2\right\} - 2]}{16 - \frac{1}{2} - 7}$$

$$\frac{8 \div [5 \div \frac{17}{8} - 2]}{ \frac{17}{2}}$$

$$\frac{8 \div [5 \times \frac{8}{17} - 2]}{ \frac{17}{2}}$$

$$\frac{8 \div [ \frac{40}{17} - 2]}{ \frac{17}{2}}$$

$$\frac{8 \div\frac{6}{17}}{ \frac{17}{2}}$$

$$\frac{8 \times \frac{17}{6}}{ \frac{17}{2}}$$

=$$\frac{8}{3}$$


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