The value of $$2\sin 12° - \sin 72°$$ is

Since $$\sin 12° = \sin(30° - 18°) = \sin 30° \cos 18° - \cos 30° \sin 18°$$, it follows that $$\sin 12° = \frac{1}{2}\cos 18° - \frac{\sqrt{3}}{2}\sin 18°$$.

Substituting this into $$2\sin 12° - \sin 72°$$ and using $$\sin 72° = \cos 18°$$ gives $$2\sin 12° - \sin 72° = 2\Bigl(\frac{1}{2}\cos 18° - \frac{\sqrt{3}}{2}\sin 18°\Bigr) - \cos 18° = \cos 18° - \sqrt{3}\sin 18° - \cos 18° = -\sqrt{3}\sin 18°$$.

Since $$\sin 18° = \frac{\sqrt{5} - 1}{4}$$, this yields $$2\sin 12° - \sin 72° = -\sqrt{3} \cdot \frac{\sqrt{5} - 1}{4} = \frac{\sqrt{3}(1 - \sqrt{5})}{4}$$. Therefore, the answer is $$\frac{\sqrt{3}(1 - \sqrt{5})}{4}$$ (Option D).