Let $$C: x^2 + y^2 = 4$$ and $$C': x^2 + y^2 - 4\lambda x + 9 = 0$$ be two circles. If the set of all values of $$\lambda$$ so that the circles $$C$$ and $$C'$$ intersect at two distinct points, is $$R - a, b $$, then the point $$8a + 12, 16b - 20$$ lies on the curve:

A

$$x^2 + 2y^2 - 5x + 6y = 3$$

B

$$5x^2 - y = -11$$

C

$$x^2 - 4y^2 = 7$$

D

$$6x^2 + y^2 = 42$$