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Six books A,B, C, D, E and F, each of different thickness, are kept on a table. C is thicker than A, but thinner than E. A is thicker than both B and D. E is not the thickest. The third thinnest book is 9 cm thick and the thickest book is 16 cm thick. (Note the thickness of all the books are in whole numbers.)
Here,
C>A and C<E
A>B and A>D
Also E is not the thickest, hence :-
F>E>C>A> B&D; (order of B and D not known, but both are thinner than A).
Hence, the 2 possible combinations :-
1. F>E>C>A>B>D
2. F>E>C>A>D>B
Also the third thinnest book i.e. A is 9cm. Thickest book i.e. F is 16 cm.
Now according to the question, E is 5 cm thicker than A, hence E = 14cm.
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