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The number of ways in which 21 identical apples can be distributed among three children such that each child gets at least 2 apples, is
21 apples, 3 children, each ≥ 2. Give 2 each first: remaining 15 among 3 with each ≥ 0. $$\binom{15+2}{2}=\binom{17}{2}=136$$.
The answer is Option (4): 136.
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