JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
The number of ways in which 21 identical apples can be distributed among three children such that each child gets at least 2 apples, is
21 apples, 3 children, each ≥ 2.
Give 2 each first: remaining 15 among 3 with each ≥ 0.
$$\binom{15+2}{2}=\binom{17}{2}=136$$.
Create a FREE account and get:
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
