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Instructions
In the following questions two equations numbered I and II are given. You have to solve both the equations and —
Give answer a: if × > y
Give answer b: if × ≥ y
Give answer c: if × < y
Give answer d: if × ≤ y
Give answer e: if × = y or the relationship cannot be established.
Solution
I. $$2x^{2} + 11x+ 14 = 0$$
=> $$2x^2 + 4x + 7x + 14 = 0$$
=> $$(2x + 7) (x + 2) = 0$$
=> $$x = \frac{-7}{2} , -2$$
II. $$2y^{2} + 17y + 33 = 0$$
=> $$2y^2 + 6y + 11y + 33 = 0$$
=> $$(2y + 11) (y + 3) = 0$$
=> $$\frac{-11}{2} , -3$$
$$\therefore$$ No relation can be established.
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