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Instructions
In the following questions two equations numbered I and II are given. You have to solve both the equations and —
Give answer a: if × > y
Give answer b: if × ≥ y
Give answer c: if × < y
Give answer d: if × ≤ y
Give answer e: if × = y or the relationship cannot be established.
Solution
I. $$3x^{2} - 17x + 24 = 0$$
=> $$3x^2 - 9x - 8x + 24 = 0$$
=> $$(3x - 8) (x - 3) = 0$$
=> $$x = \frac{8}{3} , 3$$
II. $$4y^{2} - 15y + 14 = 0$$
=> $$4y^2 - 8y - 7y + 14 = 0$$
=> $$(4y - 7) (y - 2) = 0$$
=> $$y = \frac{7}{4} , 2$$
$$\therefore x > y$$
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