Question 61

$$ K_{sp} \text{ for } Cr(OH)_3 \text{ is } 1.6\times10^{-30}.$$ What is the molar solubility of this salt in water?

Solution

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Ksp for Cr(OH)₃ = 1.6×10⁻³⁰. Find molar solubility.

$$Cr(OH)_3 \rightleftharpoons Cr^{3+} + 3OH^-$$

If solubility = s: $$K_{sp} = s(3s)^3 = 27s^4$$

$$s^4 = \frac{1.6 \times 10^{-30}}{27}$$

$$s = \sqrt[4]{\frac{1.6 \times 10^{-30}}{27}}$$

The correct answer is Option 3.

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