Question 60

X g of ethylamine is subjected to reaction with NaNO₂/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is ______ × 10⁻¹ g.

Correct Answer: 45

Ethylamine + NaNO₂/HCl → Diazonium salt → N₂ + Ethanol

C₂H₅NH₂ → N₂

At STP: Volume of N₂ = 2.24 L, so moles of N₂ = 2.24/22.4 = 0.1 mol

Moles of ethylamine = 0.1 mol (1:1 ratio)

Mass = 0.1 × 45 = 4.5 g = 45 × 10⁻¹ g

The answer is 45.

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