The length, breadth and height of a room is 21 metres, 12 metres and 16 metres. What will be the length of the largest rod that can be placed in that room?
Given, Length of the room = 21 m
Breadth of the room = 12 m
Height of the room = 16 m
Length of the largest rod placed in the room is equal to the length of its diagonal.
$$= \sqrt{21^2 + 12^2 + 16^2} = \sqrt{441+144+256} = \sqrt{841} = 29 m$$
Create a FREE account and get:
Day-wise Structured & Planned Preparation Guide
By proceeding you agree to create your account
Free CAT Schedule PDF will be sent to your email address soon !!!
