Question 60
The length, breadth and height of a room is 21 metres, 12 metres and 16 metres. What will be the length of the largest rod that can be placed in that room?
Solution
Given, Length of the room = 21 m
Breadth of the room = 12 m
Height of the room = 16 m
Length of the largest rod placed in the room is equal to the length of its diagonal.
$$= \sqrt{21^2 + 12^2 + 16^2} = \sqrt{441+144+256} = \sqrt{841} = 29 m$$
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