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We need to identify molecules with square pyramidal geometry.
$$BrF_5$$: Br has 7 valence electrons. With 5 F atoms: 5 bond pairs + 1 lone pair = 6 electron pairs. Arrangement: octahedral. With one lone pair, the shape is square pyramidal.
$$PCl_5$$: P has 5 valence electrons. With 5 Cl atoms: 5 bond pairs + 0 lone pairs. Shape is trigonal bipyramidal, not square pyramidal.
$$SbF_5$$: Sb has 5 valence electrons. With 5 F atoms: 5 bond pairs + 0 lone pairs. Shape is trigonal bipyramidal, not square pyramidal.
$$XeOF_4$$: Xe has 8 valence electrons. With 1 O (double bond) + 4 F atoms: 5 bond pairs + 1 lone pair = 6 electron pairs. Arrangement: octahedral. With one lone pair, the shape is square pyramidal.
$$BrF_5$$ and $$XeOF_4$$ both have square pyramidal geometry.
The correct answer is Option D) $$BrF_5$$ and $$XeOF_4$$.
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