Sum of oxidation states of bromine in bromic acid and perbromic acid is

We need to find the sum of oxidation states of bromine in bromic acid ($$HBrO_3$$) and perbromic acid ($$HBrO_4$$).

We start by stating the oxidation state rules. In compounds: Hydrogen has oxidation state $$+1$$, and Oxygen has oxidation state $$-2$$. The sum of all oxidation states in a neutral molecule equals zero.

Next, to find the oxidation state of Br in $$HBrO_3$$ (bromic acid), let the oxidation state of Br be $$x$$. Substituting into the rule gives $$ (+1) + x + 3(-2) = 0 $$. This simplifies to $$ 1 + x - 6 = 0 $$, yielding $$ x = +5 $$.

Then, to find the oxidation state of Br in $$HBrO_4$$ (perbromic acid), let the oxidation state of Br be $$x$$. Substituting gives $$ (+1) + x + 4(-2) = 0 $$. Simplifying $$ 1 + x - 8 = 0 $$ leads to $$ x = +7 $$.

Therefore, the sum of the oxidation states is $$ \text{Sum} = 5 + 7 = 12 $$. The answer is 12.