Sum of oxidation states of bromine in bromic acid and perbromic acid is

We need to find the sum of oxidation states of bromine in bromic acid and perbromic acid.

For bromic acid ($$HBrO_3$$), let the oxidation state of Br be $$x$$:

$$+1 + x + 3(-2) = 0$$, so $$x = +5$$.

For perbromic acid ($$HBrO_4$$), let the oxidation state of Br be $$y$$:

$$+1 + y + 4(-2) = 0$$, so $$y = +7$$.

Hence, the sum of oxidation states = $$5 + 7 = 12$$. So, the answer is $$12$$.