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The carbonyl group of the lactone becomes an aldehyde ($$-\text{CHO}$$).
The ring-fusion oxygen is protonated to form a hydroxyl group ($$-\text{OH}$$) remaining on the cyclopentadiene ring
The $$-\text{COOH}$$ group attached to the lower part of the ring is converted into a $$-\text{CHO}$$ group.
Option A correctly shows the addition of the hydroxyl group to the ring and the conversion of both the lactone and the carboxylic acid into aldehydes.
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