In a certain code, every $$n^{th}$$ letter in the English alphabet is coded as $$r^{th}$$ letter where r is the remainder when $$5n + 7$$ is divided by 26 and $$1 \leq r \leq 26$$. For example, the $$10^{th}$$ letter J is coded as $$5^{th}$$ letter E, since $$(5 \times 10) + 7 = 57 = (2 \times 26) + 5$$. For decoding the reverse process is followed. Based on this answer the questions.
In the given code, the numberof letters which are coded as immediate nextletter in the alphabet is
Create a FREE account and get:
- Download Maths Shortcuts PDF
- Get 300+ previous papers with solutions PDF
- 500+ Online Tests for Free
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
