In a certain code, every $$n^{th}$$ letter in the English alphabet is coded as $$r^{th}$$ letter where r is the remainder when $$5n + 7$$ is divided by 26 and $$1 \leq r \leq 26$$. For example, the $$10^{th}$$ letter J is coded as $$5^{th}$$ letter E, since $$(5 \times 10) + 7 = 57 = (2 \times 26) + 5$$. For decoding the reverse process is followed. Based on this answer the questions.
In the given code, the numberof letters which are coded as immediate nextletter in the alphabet is
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