Instructions

In a certain code, every $$n^{th}$$ letter in the English alphabet is coded as $$r^{th}$$ letter where r is the remainder when $$5n + 7$$ is divided by 26 and $$1 \leq r \leq 26$$. For example, the $$10^{th}$$ letter J is coded as $$5^{th}$$ letter E, since $$(5 \times 10) + 7 = 57 = (2 \times 26) + 5$$. For decoding the reverse process is followed. Based on this answer the questions.

Question 57

In the given code. the numberofletters which are coded as themselves is


Create a FREE account and get:

  • Download Maths Shortcuts PDF
  • Get 300+ previous papers with solutions PDF
  • 500+ Online Tests for Free

cracku

Boost your Prep!

Download App