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For a reaction, $$N_2O_5(g) \rightarrow 2NO_2(g) + \frac{1}{2}O_2(g)$$ in a constant volume container, no products were present initially. The final pressure of the system when $$50\%$$ of reaction gets completed is:
$$N_2O_5 \rightarrow 2NO_2 + \frac{1}{2}O_2$$. Find final pressure when 50% reacts.
Initial: Pâ‚€ (Nâ‚‚Oâ‚… only)
At 50% decomposition: N₂O₅ = P₀/2, NO₂ = 2(P₀/2) = P₀, O₂ = ½(P₀/2) = P₀/4
Total = Pâ‚€/2 + Pâ‚€ + Pâ‚€/4 = 7Pâ‚€/4
The correct answer is Option 4: $$\frac{7}{4}$$ times initial pressure.
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