Consider the following data.

Electrolyte	$$\Lambda^\circ_m$$ (S cm$$^2$$ mol$$^{-1}$$)
BaCl$$_2$$	$$x_1$$
H$$_2$$SO$$_4$$	$$x_2$$
HCl	$$x_3$$

BaSO$$_4$$ is sparingly soluble in water. If the conductivity of the saturated BaSO$$_4$$ solution is $$x$$ S cm$$^{-1}$$ then the solubility product of BaSO$$_4$$ can be given as
(Here $$\Lambda_m = \Lambda^\circ_m$$)

A

$$\frac{10^6 x^2}{a^2(x_1 + x_2 - 2x_3)^2}$$

B

$$\frac{x^2}{(x_1 + x_2 - 2x_3)^2}$$

C

$$\frac{a^2(x_1 + x_2 - 2x_3)^2}{10^6 x^2}$$

D

$$\frac{x^2}{(x_1 + x_2 + 2x_3)^2}$$